4. In 2007
08, the number of students appeared for Class X examination was
1,05,332 and in 2008-09, the number was 1,16,054. If 88,151 students pass the
examination in 2007-08 and 103804 students in 2008-09. What is the increase or
decrease in pass % in Class X result?
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Answer:
Given, In 2007−08,
The number of student appeared for Class X
examination =1,05,332
In 2008−09, the number =1,16,054
Passed % of student in 2007−2008
= { (Number of student appeared in 2007−2008) / (Number of student passed in 2007−2008) } ×100
= (105332 / 88151) ×100
=83.68%
Passed % of student in 2008−2009
= { (Number of student appeared in 2008−2009) /
(Number of student passed in 2008−2009) } ×100
= (116054 / 103804) ×100=89.44%
So, increased %
= (89.44−83.68)
= 5.76%
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