4. In a AABC, AD bisects angle BAC and AD = DC. If angle BDA = 70°, calculate angle ACD and angle ABD.
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Answered by
1
Correct option is
A
30
o
Given AD=DC
∴∠DAC=∠DCA
In ΔADC,
External of ∠ADC=∠DAC+∠DCA=100
o
∴∠DAC=∠DCA=
2
100
=50
o
Now, AD bisects ∠BAC
⇒∠BAD=50
o
∴ In ΔABD,
∠ABD=180−(100+50)=30
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Answer:
answer is 30 degree hope it helps you
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