4. In a ∆ABC, if ∠A =60˚, ∠B =80˚and the bisectors of ∠B and ∠C meet at O, then ∠BOC =
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Answer:
answer is 120°
Step-by-step explanation:
∆ABC=60°+80°+X=180°
x=(60+80)-180
x=40
i.e \_ c= 40°
as angle b is bisector so that will the divide angle into half part so
20+40+y=180
y=(20+40)-180
y=120
angle BOC = 120°
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