Question

4] In a triangle, the sum of measures of two ongles is equal to the measure
of third angle. If the difference between them is 50' find the measures of
all the three angles.
Solution​

Answer 1

Let one of the angle be x°.

Then the second angle = (x-50)°

Therefore, the third angle = [x + (x-50)]°

We know, the sum of all the angles of a triangle is 180°.

Therefore, by the problem

x + (x-50) + [x + (x-50)] = 180

or x + x - 50 + x + x - 50 = 180

or 4x - 100 = 180

or 4x = 180+100

or 4x = 280

or x = 280/4 = 70

Therefore, the measures of the angles are 70°, (70-50)°, i.e., 20° and [70 + (70-50)]° i.e., 90°.

Answer: The measures of the three angles are 70°, 20° and 90°.

Answer 2

Answer:

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Step-by-step explanation:

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