Question

4. In
ABC, if ZA+ZB = 108° and ZB+ ZC = 130°, find ZA, ZB and Zc​

Answer 1

Answer:

In ∆ABC ,

Angle C = angle A + 30° ------(1)

Angle A = angle B - 15°

Angle B = angle A + 15° -------(2)

We know that sum of the three angles of a

triangle = 180°

then ,

Angle A + Angle B + Angle C = 180°

Angle A + (Angle A + 15°) + (Angle A + 30°)= 180°

b3Angle A + 45° = 180°

3Angle A = 135°

Angle A = 45°

then , Angle B = 60°

Angle C = 75°