Question

(4) In an A. P. if a = 2 and t⁵
12, find t²,t³,t⁴



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Answer 1

$\mathbb\red{Given:-}$

• First term (a)is 2
• fifth term is 12

$\mathbb\red{To\:find :-}$

• second ,third and fourth term of AP

Solution:-

• as we know
• a+4d=12
• put value of a
• 2+4d=12
• 4d=10
• d=$\frac{5}{2}$

Now value of a is$\mathbb\red{2}$

and value of d is $\mathbb\red{ \frac{5}{2} }$

Now lets find second term

• a+d
• 2+$\frac{5}{2}$
• $\frac{9}{2}$

Third term

• a+2d
• 2+2$\frac{5}{2}$
• 7

Fourth term is

• a+3d
• 2+3$\frac{5}{2}$
• 2+$\frac{15}{2}$
• $\frac{19}{2}$

hence the AP is

2,$\frac{9}{2}$,7,$\frac{19}{2}$,12