Question

4. In APQR, ZQ = 90° and PQ = QR = 6 cm.
Calculate the
(i) area of triangle
(ii) length of perpendicular from Q to PR
[Take 2 = 1.414]​

Answer 1

Answer:

Ratio of the angle in thetriangle

=l:I:2

so the sides opposits are l:l: v2

length of Side P Q and Q Rare

6cm each

area= 1/2bh = 6x6/2=18cm2

hypoten use=v6^2+6^2 =v36+36

v72=6v2 = 6x1.414=8.484 cm

perpendicular be h

bh/2 = 18

h = 18x2/8.484=36/8.484=4.48

perpendicular from Qto PR=4:48 cm