Question

4.
in Fig 1 PO and PR are tangents to the circle
with centre o such that OPR-50"
thon OOR s equal to

​

Answer 1

Please post the question properly!!

Answer 2

Answer:

In mathematical sentance,

PQ = QR

•°•It made an isosceles triangle

PQR = 180°

2Q = 180 - 50

Q = 130/2

•°•Q = 65

Now,

Angle OPQ = 90°

In which RQP= 65°

So,

Angle OQR = 90 - 65

= 25

Hence

The angle is 25°

Hope it helps you.....