4. In Fig. 14.30, calculate:
a) the length of AB
b) area of trapezium ABCD
c) area of ABCD
12 cm
C
26 cm
10 cm
А A
B В
Fig. 14.30
Answers
Answered by
14
Answer:
ADB is a triangle
thus p2 +b2=h2
√(26)2-(10)2=√36 x16[(a2-b2=(a+b)(a-b)]
=24
thus AB =24 cm
area of trapezium =1/2*h*( sum of parallel sides)
=1/2*10*(24+12)=1/2*10*36=180
area of ABCD= 180cm2
or you could subtract the area , as
area of ABCD-Area of ADB
=180-(1/2*24*10)
180-120=60cm2 =area of BCD
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
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