4. In Fig. 6.16, if x + y=w+z. then prove that AOB is a line.
Answers
In Fig. 6.16, if x + y=w+z. then prove that AOB is a line.
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Sum of all angles in a circle always 360°
Hence
∠AOC + ∠BOC + ∠DOB + ∠AOD = 360°
=> x + y + w + z = 360°
=> x + y + x + y = 360°
Given that x + y = w + z
Plug the value we get
=> 2w + 2z = 360°
=> 2(w + z) = 360°
w + z = 180° (linear pair)
or ∠BOD + ∠AOD = 180°
If the sum of two adjacent angles is 180°, then the non-common arms of the angles form a line
Hence AOB is a line.
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All necessary formulas⤵️
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Angle sum property of triangle states that the sum of interior angles of a triangle is 180°. Proof .Thus, the sum of the interior angles of a triangle is 180°.
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Alternate interior angles are angles formed when two parallel or non-parallel lines are intersected by a transversal.Alternate interior angles are equal if the lines intersected by the transversal are parallel.
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The sum of 2 numbers
example
how to find "a" if a is not mentioned
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The sum of two numbers
example
how to find "a" if a is not mentioned
Given
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If there is a common ray between and so it is a adjacent angle.
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Vertical angles are pair angles formed when two lines intersect. Vertical angles are sometimes referred to as vertically opposite angles because the angles are opposite to each other.
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Here 180°.
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GIVEN
- x + y = w + z
TO PROVE
- AOB is a line
SOLUTION
- x + y + w + z = 360∘
- (x+y) + (w+z) = 360∘
- (x+y) + (x+y) = 360∘
Given x + y = w + z
- 2(x + y) = 360∘
- (x + y) = 180∘
Here, x + y is a linear pair.
Hence, AOB is a straight line