Question

4. In Fig. 9.16, P is a point in the interior of a
parallelogram ABCD. Show that
Р
mar (APB) + ar (PCD) = -1
ar (ABCD)
D
(
ar (APD)+ ar (PBC)=ar (APB)+ ar (PCD)
(Hint: Through P, draw a line parallel to AB.)
Fig. 9.16​

Answer 1

Answer:

where is the picture we are not able to see the fig