Math, asked by imranansari62, 5 months ago

4. In Fig. 9.9, find the sum of angles 1, 2, 3, 4, 5, 6, 7, 8 and 9.​

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Answered by sd794582
0

Answer:

45 is the answer of this question

Answered by DHRITIMITTAL
0

Step-by-step explanation:

Angle 8 and 2 = 108° (because it is a pentagon)

In Triangle ADE,

AE=DE

By angel sum property of Triangle

Angle 9 and 7 =36° (AE = DE)

In Triangle ABC,

AB=CB

By angel sum property of Triangle

Angle 1 and 3=36° (AE = DE)

As all angles of a pentagon r same so,

Angel D=108°

Angle 7 + Angle 6=Angle D

36° + Angle 6=108°

Angle 6 = 108°-36°

Angle 6 = 72°

Angel C=108°

Angle 3+ Angle 5=Angle C

36° + Angle 5=108°

Angle 5= 108°-36°

Angle 5 = 72°

Angel A=108°

Angle 1 + Angle 4 + angle 9=Angle A

36° + Angle 4 +36°=108°

Angle 4 + 72°= 108°

Angle 4 = 108°-72°

Angle 4 = 36°

Sum of angles = 540°

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