Question

4 in fig.PM=10 cm A{ APQS) = 100sqcm AC AQRS) = 110sqcm then NR?
APQS &AQRS having seg QS common base
Areas of two triangles whose base are common, are in proportion of
their corresponding
100NR [-] cm
ACAQRS)
whoever ans correct i will mark it branliest​

Answer 1

Answer:

NR = 11 cm

Step-by-step explanation:

Given:

PM = 10 cm

A(∆PQS) / A(∆QRS) = 100/110

now,

=>( 1/2 * PM * QS ) / ( 1/2 * NR * QS ) =100/110

=> 10/NR = 100/110

=> NR = 11 cm

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