Question

4.
In fig. ZAOB = 90°, AC = BC, OA = 12 cm and OC = 6.5 cm. Find the area of A AOB.
A
C С
12am
B​

Answer 1

Step-by-step explanation:

mid-point of the hypotenuse of a right triangle is equidistant from the vertices.

∴CA=CB=OC⇒CA=CB=6.5 cm⇒AB=13 cm

In right triangle OAB, we have

AB

2

=OB

2

+OA

2

⇒13

2

=OB

2

+12

2

⇒OB=5

∴ar(△AOB)= 21

(OA×OB)= 21

(12×15)=30 cm sq

Answer 2

Answer:

Step-by-step explanation:

mid-point of the hypotenuse of a right triangle is equidistant from the vertices.

∴CA=CB=OC⇒CA=CB=6.5 cm⇒AB=13 cm

In right triangle OAB, we have

AB

2

=OB

2

+OA

2

⇒13

2

=OB

2

+12

2

⇒OB=5

∴ar(△AOB)= 21

(OA×OB)= 21

(12×15)=30 cm sq