Math, asked by gautamgargefg, 5 months ago


4. In how many ways can 5 persons A, B, C, D and E sit
around a circular table if :
(i) B and D sit next to each other?
(ii) A and D do not sit next to each other?​

Answers

Answered by palakpandey351
5

Answer:

12

Step-by-step explanation:

A ξ B not sit together = Total −(AξBsittogether)

⇒ Total permutation =(5−1)!=4!=24

A ξ B sit together : AξB should be considered as 1 entity so now 4 entities to be seated =3!, But AξB can interchange their places,

∴3!×2!=12

⇒ Required =24−12=12

Hence, the answer is 12.

Answered by manojponnan74
1

Answer:

12

Step-by-step explanation:

b and d sit together d sit between b and c and a sit next c

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