4. In square ABCD, APAB is equilateral. Find
the value of x in the figure.
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Step-by-step explanation:
consider right triangle ABC we know that
AB =BC (SINCE both are sides of square)
angle BAC=angleBCA(isosceles triangle)
angle B= 90°(angle of square)
by sum of angle of triangle
angle BAC&BCA = 45°
now consider equilateral triangle PAB
angle P =60° (angles of equilateral triangle)
we know that angle CAB is 45°
and angle PAB is 60°( angle equilateral triangle)
so angle PAC =60°-45°=15°
in triangle APO(small triangle in fig)
external angle of triangle x= sum of opposite internal angles
that is
x=60°+15°
=75
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