Question

4. In square PQRS :
(i) if PQ = 3x - 7 and QR = x + 3; find PS.
(ii) if PR = 5x and QS = 9x - 8. Find QS.​

Answer 1

Answer:

i) 8

ii)10

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Step-by-step explanation:

i) We know that in a square all sides are equal.

i.e. PQ = QR = RS = PS

3x - 7 = x + 3

2x = 10

x = 5

Since QR = PS,

x + 3 = PS

PS = 8

ii) PR = 5x

QS = 9x - 8

PR and QS are diagonals of a square.

Diagonals of a square are equal.

i.e. PR = QS

5x = 9x - 8

4x= 8

x = 2

QS = 9x - 8

= 9(2) - 8

QS = 10