Question

4. In the adjacent figure AB || CD. O is the mid-point
of BC. Prove that O is also the mid-point of AD.
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Answer 1

Answer:

if DO = OA then O will be the mid point of AD

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Answer 2

Step-by-step explanation:

Given: AB || CD

          BO=CO (since O is the midpoint)

To prove : AO =DO

Proof : angle BCD = angle CBA (alternate interior angles)

           CO=BO (given)

           angle COD = angle BOA (V.O.A)

         therefore,

                    ΔCOD ≅ ΔBOA (ASA)

           ⇒ DO=AO

           ⇒ O is the midpoint of AD

 HENCE PROVED

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