4. In the adjoining figure, ABCD is a square and AEDC is an equilateral triangle. Prove that (i) AE = BE, (i) DAE = 15°. D A B
probed it in simple words
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2892999.2992992 9i ste answers
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let us take that triangle DEA is similar to triangle CEB BY SSS Similarity so corresponding sides are equal so u got 1 ans I got only first ans
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