Question

4. In the equations of motion, acceleration a and
distance s are replaced by what terms for freely falling bodies?​

Answer 1

Explanation:

For freely falling bodies, the acceleration due to gravity is 'g', so we replace the acceleration 'a' of the equations by 'g' and since the vertical distance of the freely falling bodies is known as height 'h', we replace the distance 's' in our equations by the height 'h'.

What are the equations of motion for a freely falling body?

Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s/s for any freely falling object. If an object is merely dropped (as opposed to being thrown) from an elevated height, then the initial velocity of the object is 0 m/s.

What is the acceleration associated with free fall called?

A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). ... It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity.

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Answer 2

Equations of motion for freely falling bodies :-

• v = u + at changes to v = u + gt

• s = ut + ½ at² changes to h = ut + ½ gt²

• v² = u² + 2as changes to v² = u² + 2gh

Points to remember :-

• When a body is freely vertically upwards, its velocity is decreasing,so the acceleration due to gravity, g is taken positive.

• When a body is thrown vertically upwards,its velocity is decreasing, so the acceleration due to gravity, g is taken as negative.

• When a body is dropped freely from a height, its initial velocity 'u' is zero.

• When a body is thrown vertically upwards, its final velocity 'v' becomes zero.

• The time taken by a body is rise to the highest point is equal to the time it takes to fall from the same height.