Question

* 4. In the figure, angle PQR = 122°, angle QRS = x and
angle RST = y.

What can be the possible values of x and y
so that ray QP || ray ST? (HOTS and Open
ended question)​

Answer 1

Answer:

x + y = 238

x = y + 58

y = x + 122

Step-by-step explanation:

PQR   + QRS + RST  = 360°

=> 122° + x  + y = 360°

=> x + y = 238°

x + y = 238

Now if ST is just turned at 180°

then  y = 180 - y

x  + (180 - y) = 238

=> x = y + 58

or if y is taken other side the y = 360 -y

=> x + (360 - y)  = 238

=> y = x + 122

Answer 2

one of the possible value can be X = 50° and Y = 180°.