С
4. In the figure, seg AB = seg AC, B-A-E and
ray AD bisects EAC then prove ray AD | side BC.
Answers
Answered by
1
Answer:
CE is angle bisects of ACB
From vertical angle bisects theorem.
EB
AE
=
BC
AC
−−−−(1)
BD is angle bisects of ABC
From vertical angle bisects theorem,
DC
AD
=
BC
AB
=
BC
AC
(∵ AB=AC)−−−−(2)
From (1) & (2)
EB
AE
=
DC
AD
So, ED is parallel to BC.
Attachments:
Similar questions