Question

4. In the following figure CDI AB,'O' is the mid point of AD then following
which
is correct answer. . (A) ZDCO = 20AB
(C) 2CDO = 20AB
C=
(B) <COD = ZOBA
(D) ZCDO = ZOBA​

Answer 1

Step-by-step explanation:

In triangles AOC and BOD, we have

AO = BO (O, the midpoint of AB);

∠AOC=

∠BOD

, (vertically opposite angles);

CO=

OD

, (O, the midpoint of CD)

So by SAS postulate we have

△AOC≅

△BOD

.

Hence, AC = BD, as they are corresponding parts of congruent triangles.