Question

4. In the given circuit , calculate

a. Total resistance

b. Current in the circuit

c. Potential difference across R1 and R 2​

Answer 1

In the given circuit , we are given two resistors of resistances 6 Ω and 30 Ω , which are connected in series and a battery of 9 Volts .

a .

• When resistors are connected in series , Eq. resistance will be found by adding the individual resistances

➠  $\sf{\orange{R_{eq}=R_1+R_2}}\ \; \bigstar$

Let , R₁ = 6 Ω & R₂ = 30 Ω

So , Eq. resistance = 6 Ω + 30 Ω

➤ Eq. resistance = 36 Ω  $\pink{\bigstar}$

b.

• Ohm's law states that , Potential difference in the circuit is directly proportional to the current passing in the circuit  

➳ V = I Rₑ₉

➳ I = 9 / 36

➳ I = 1 / 4

➳ I = 0.25 A  $\green{\bigstar}$

c.

Potential difference across R₁ :

V = IR₁

V = (0.25) (6)

V = 1.5 V  $\red{\bigstar}$

Potential difference across R₂ :

⭆ V = IR₂

⭆ V = (0.25)(30)

⭆ V = 7.5 V  $\purple{\bigstar}$