Question

4. In the given figure, TPQ = 111° and TRS = 164º. Find the value of x.​

Answer 1

Answer:

by the linear pair

angle prq + 164 = 180

prq = 16°

similar in angle tpq( inner angle)

by linear pair

tpq = 69°

in triangle pqr

16 +69 + angle pqr = 180

pqr = 180 - 85

pqr = 95°

by linear pair

95° + x = 180

x = 180-95

x = 85°

Answer 2

Hello.....

Refer this attachment

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