Question

4. In the given rectangle ABCD (Fig. 2),
BP = BC. What is the measure of angle PCD?
plz i need ans of this soon
step by step
plzzz​

Answer 1

Answer:

we have to calculate the work done on charge 1 C in an electrostatic field 2 N/C along x - axis when charge is moved through a distance 2.5 m along +x axis.

solution : we know force, F = qE

where q is charge and E is electrostatic field.

here q = 1 C and E = 2 N/C along x - axis

so the force along x - axis , F = 1 C × 2N /C = 2 N

displacement along x - axis , s = 2.5 m

work done = force × displacement along force

= 2 N × 2.5 m

= 5 Nm = 5J

Therefore the workdone on the charge 1 C in an electrostatic field 2 N/C along x - axis is 5 J