Question

4. In the given trapezium ABCD, side AB | side DC.
AMI DC and BNI DC.
If I(AB) = 20, 1(BC) = 13,
I(NC) = 5,1(AD) = 15 then I(DC) = ?​

Answer 1

Answer:

Since, ∠COD=∠AOB (opposite angle) , ∠CDO=∠OBA (transversal angle) and ∠DCO=∠OAB (transversal angle).

Then

AB

CD

=

OA

OD

or,

20

6

=

15

OD

or, OD=4.5