Question

4. In the map of a triangular field, sides are shown by 8 cm, 7 cm and 6 cm. If the
largest side of the triangular field is 400 m, find the remaining sides of the field.
(Application)​

Answer 1

Answer:

first side is 350m and second is 300m.

Step-by-step explanation:

400/8=50

here we took the ratio of larger side to its representative size in map...

Now multiple representative size in map by 50m.

7×50=350 m --> first side

6×50=300 m --> second side

Answer 2

The lengths of the remaining sides of the field are 350m and 300m

Given : In the map of a triangular field, sides are shown by 8 cm, 7 cm and 6 cm. If the largest side of the triangular field is 400 m.

To find : The lengths of the remaining sides of the field.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the lengths of the remaining sides of the field)

Length of the largest side of the field = 400m = 400 × 100 = 40000cm

(As, 1 m = 100 cm)

Length of the largest side on the map = 8cm

(As, 8cm > 7cm > 6cm)

So,

8cm on map means = 40000cm of actual length

1 cm on map means = (40000/8) = 5000cm of actual length

Length of remaining sides on map = 6cm and 7cm

Now,

1 cm on map means = 5000cm of actual length

7 cm on map means = (5000 × 7) = 35000cm of actual length

And,

1 cm on map means = 5000cm of actual length

6 cm on map means = (5000 × 6) = 30000cm of actual length

The lengths of the remaining sides :

1. 35000 cm = (35000 ÷ 100) = 350m
2. 30000 cm = (30000 ÷ 100) = 300m

(As, 100cm = 1m)

Hence, the lengths of the remaining sides of the field are 350m and 300m