Question

4. In trapezium ABCD, M and N are mid-points of
AC and BD, and AB || CD. Find
(i) MN if AB = 7.5 cm, CD = 5.5 cm
(ii) AB if CD = 16 cm, MN = 10 cm
(iii) CD if AB = 14 cm, MN = 16.5 cm
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Answer 1

Answer:

Given :-. In trapezium ABCD, M and N are mid-points of AC and BD, and AB II CD. Find

(ii) AB if CD = 16 cm, MN = 10 cm

(1) MN if AB = 7.5 cm, CD = 5.5 cm

(iii) CD if AB = 14 cm, MN = 6.5 cm

(i) MN if AB = 7.5 cm, CD = 5.5 cm

since,

→ MN = (1/2)[AB - CD] .

SO,

→ MN = (1/2)[7.5 - 5.5]

→ MN = (1/2) * 2

→ MN=1 cm.

(ii) AB if CD = 16 cm, MN

MN = (1/2)[AB - CD] .

→ 1O = (1/2)[AB - 16]

→ 20 = AB - 16

→ AB = 36 cm.

= 10 cm

(iii) CD if AB = 14 cm, MN = 6.5 cm.

MN = (1/2)[AB - CD] .

→ 6.5 = (1/2)[14 - CD]

→ 13 = 14 - CD .

=CD=1cm

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