4. In Triangle ABC, AC = BC. DE is drawn parallel to BC through A. angle EAC = 42º. Find angle x...
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Answer:
total = 180°
so,
x+42=180
x=180-42
x=138°
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0
Answer:
x=69°
Step-by-step explanation:
DE parallel to BC therefore angle BAC is equal to angle ACB alternate interior angles. therefore angle ACB is equal to 42 degree as triangle ACB is an isosceles triangle there for angle c a b is equal to angle CBA therefore
2x+42 =180° (angle sum property of triangle)
2x+=138
x=69°
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