4 is a zero of the cubic polynomial p(x)=x³-3x²-6x+8
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HEYA!!
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Put X : 4 in the equation p(x).
(4) ^3 - 3 (4)^2 - 6×4 +8
64 - 3 × 16 - 24 +8
64-48 - 24 +8
72 - 72 = 0
Hence p(x) = 0 for x=4
Hence X is a zero of the polynomial.
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Put X : 4 in the equation p(x).
(4) ^3 - 3 (4)^2 - 6×4 +8
64 - 3 × 16 - 24 +8
64-48 - 24 +8
72 - 72 = 0
Hence p(x) = 0 for x=4
Hence X is a zero of the polynomial.
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DevilDoll12:
:-)
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