Question

4. Is the function f(x) = cot x derivable at x = 0?
​

Answer 1

Answer:

I think NO because cot0° will be infinite.

Answer 2

SOLUTION

TO CHECK

Is the function f(x) = cot x derivable at x = 0

EVALUATION

Here the given function is

f(x) = cot x

Differentiating both sides with respect to x we get

f'(x) = - cosec² x

Thus we get

$\displaystyle \sf{f'(x) = - \frac{1}{ { \sin}^{2} x} }$

Now sinx vanishes at x = 0

Thus f'(0) does not exist

Hence the function f(x) = cot x is not derivable at x = 0

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If integral of (x^-3)5^(1/x^2)dx=k5^(1/x^2), then k is equal to?

https://brainly.in/question/15427882

2. If integral of (x^-3)5^(1/x^2)dx=k5^(1/x^2), then k is equal to?

https://brainly.in/question/15427882