4 J of energy is gained by one Coulomb of charge passing through a battery whose one terminal has
+7 V potential and the other terminal has 'X' V potential. What is the value of X?
(A) -28
(B)-3
(C) +3
(D)-11
(E) +28
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Answer:
Explanation:
Energy E=qΔV
Charge q=1 C
Potential difference ΔV=6 volts
So, E=1×6=6 J
I am wright ma be
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