4 J of energy is gained by one Coulomb of charge passing through a battery whose one terminal has
+7 V potential and the other terminal has X V potential. What is the value of X?
(A) -28
(B) -3
C) +3
D) -11
(E) +28
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Answer:
w= qV
4= 1×(7-x)
4= 7-x
x= 3 v
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