4 kg of ice at -20°C is mixed with 10 kg of water at 20°C in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. Given: Specific heat capacities of water and ice are 4.8 kJ K-1 kg-1 and 2.092 kJ K-1 kg 1, respectively. Molar enthalpy of fusion of ice is 334.7 kJ kg ?
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Ice of (- 20)℃ to 0℃ = 20 × 0.5 × 4 × 10^3
= 40 × 10^3 cal.
Ice of (+ 20)℃ to 0℃ = 20 × 1 × 10 × 10^3
= 200 × 10^3 cal.
=> (200 × 10^3 cal)/(40 × 10^3 cal.) = 5 kg
excess energy (heat) = 80 × 10^3 cal.
heat of. ice = 80 cal/gm
=> (80 × 10^3 cal.)/(80 cal/gm)
= 10^3 gm = 1 kg
Total = (5 kg + 1 kg) = 6 kg
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