4 Kj If the radius of an atom of an element is 75 pm and the lattice is body-centred cubic, the edge of the unit cell will be (1) 32.475 pm (2) 173.2 pm (331.5 pm (4) 212.1 pm
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Answer:
For body centered cubic lattice, the relationship between the edge length a and the radius r is as given below:
a=
3
4r
Substituting values in the above expression, we get
a=
3
4×75
=173.2 pm
Hence, the edge length of the unit cell is 173.2 pm
Explanation:
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