Question

4 km travelling one train cove 3/10km distance with its constant aecselaration then 30 km/hr he cover 3 km distance find how many time train in motion​

Answer 1

Answer:  Let the speed of the train be xkm/h and the time taken by train to travel the given distance be t hours and the distance to travel be dkm. We know that,

⇒Speed=  

Time

Distance

​  

 

⇒x=  

t

d

​  

 

∴d=xt.......(i)

Case 1

⇒(x+10)×(t−2)=d

⇒xt+10t−2x−20=d

⇒d+10t−2x−20=d

⇒−2x+10t=20...... (ii)

Case 2

⇒(x−10)×(t+3)=d

⇒xt−10t+3x−30=d

⇒d−10t+3x−30=d

⇒3x−10t=30......... (iii)

Adding equations (ii) and (iii), we gets  

⇒x=50

Substitute the value of x in (ii) we gets

⇒(−2)×(50)+10t=20

⇒−100+10t=20

⇒10t=120

⇒t=12 hours

Substitue the value of t  and x in  equation (i), we gets

Distance to travel =d=xt

⇒d=12×50=600Km

 

Hence, the distance covered by the train is 600km.

 

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