Chemistry, asked by Anonymous, 6 months ago

4 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. The reaction is given below:
2N2(g) + 02(g) —> 2N20(g)
Which law is being obeyed in this experiment? Write the statement of the law.

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Answers

Answered by Anonymous
16

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ʜᴇʀᴇ ɪꜱ ᴜʀ ᴀɴꜱᴡᴇʀ

2N (g)+O 2 (g)⟶2N 2O(g)

45.4 L 22.7 L

45.4 L

V∝ Number of moles ⇒ Gay Lussac Law is obeyed

Also, Reaction happen in 2:1 mole ratio of N

2 and O2

Law of definite proportion is also obeyed.

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Answered by InsaneBanda
41

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2 N{}^{2} (g) + O{}^{2} ⟹2N {}^{2}O(g) \\ 45.4l \:  \:  \:  \:  \: 22.7l \\  \\ 45.4l

V \alpha Number of moles ⟹Gay Lussac Law is obeyed

Also, Reaction happen in 2:1 mole ratio of N² and O²

Law of definite proportion is also obeyed.

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