4 L sample of gas at 30°c and I atm is charged to 0°C
and 800 torr. What is the new volume ?
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Explanation:
given that,
V1=4L
P1 = 1atm = 760torr
T1=30°C= (273+30)K =303K
T2= 0°C =273K
P2= 800torr
V2=???
from the combine formula of boyle's and charle's gas theory we get,
P1.V1/T1 = P2.V2/T2
>>760×4/303 =800×V2/273
>>V2 = (760×4×273)/(303×800)
So the answer is
V2 = 3.423
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