Question

4.
Let R be a ring. Then (0) and R itself are known as​

Answer 1

Answer:

$\large{\underline{\rm{\red{SOLUTION :}}}}$

Step-by-step explanation:

if R is an integral domain and Char R = 0, then Char R must be a prime number. ... Let Z[i] be the ring of Gaussian integers a + bi, where i = ... addition, so we know what it means for f to be a group homomorphism: f(a+b) = f(a)+f(b) ... form a group under addition, and the group is abelian because R itself is an abelian group.