Question

4 letters are to be posted in 4post boxes if any number of letter can be posted in any of the 4post boxes what is the probability that each boxcontains only one letter​

Answer 1

Answer:

P(the probability of only one letter ) = no. Of out come/sum of observation=1/4

Answer 2

Step-by-step explanation:

Total no. of outcomes = 4*4*4*4 = 4⁴ = 256

No.of favourable outcomes = 4! = 24

Therefore, probability that each box contains only one letter = 24/256 =3/32

So, required probability is 3/32

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