Question

4 litre of water are added to 2litre of 6 molar HCL solution .what is the molarity of resulying solution?​

Answer 1

Explanation:

The number of moles of HCl originally present does not change. Only the concentration of the solutions change .

original moles of solution,n1 = final moles of solution,n2- - -1

molarity(M)=no. of moles of solute/ vol of solution in litre

therefore

n1=Vol 1*M1- - -2

n2 =Vol 2*M2- - -3

on equating 1,2&3 we get,

Vol1M1 = Vol2M2

Vol1 = 2 liters

M1 = 6 M

Vol2 = 6 liters ( original 2 + 4 liters added)

M2 = ?

( 2 L )(6M)=( 6 L) (?)

on solving we get,

M2 =final molarity = (2L x 6M)/6L = 2 M