4. Locate the centre of mass of two lead spheres of radii 0.02 m and 0.04m kept so that the distance
between their centres is 0.09 m.
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Explanation:
COM = (m1x1+ m2x2)/m1+m2
= [m1(0) +m2(0.02+0.09+0.04)]/m1+m2
= ¶ 4/3 π(0.04)^3(0.15)/¶4/3π[(0.02)^3 + (0.04)^3]
= 0.0000096/0.000008+0.000064
= 0.0000096/0.000072
= 0.13 m
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