Question

4 log 4+ 2log5 - log 15 as a single logarim

Answer 1

given 4 log 4 + 2 log 5 - log 15

 log 4^4 + log 5^2 - log 15

log 256 + log 25 - log 15

 log (256 x 25) - log 15

   log 6400 - log 15

    log 6400/15

log 1280/3

log a + log b = log ab

log a - log b = log a/b

Answer 2

Hey there! Thanks for the question

4 log 4 + 2 log 5 - log 15

= log 4^4 + log 5 ^ 2 - log 15

= log ( 4 ^ 4 * 5 ^ 2 ) - log 15

$= log( \frac{ {4}^{4} \times {5}^{2} }{15} ) \\ \\ = log( \frac{256 \times 5}{3} ) \\ \\ = log( \frac{1280}{3} )$

Hope helped!