Question

4 log3base 9 +9log4base 2=10 log83 base x

Answer 1

Hi Friend !!!

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$4 log_{9}(3) + 9 log_{2}(4) = 10 log_{x}(83) \\ \\ 4 log_{ {3}^{2} }(3) + 9 log_{2}( {2}^{2} ) = 10 log_{x}(83) \\ \\ \frac{4}{2} + 9 \times 2 = 10 log_{x}(83) \\ \\ 2 + 18 = 10 log_{x}(83) \\ \\ \frac{20}{10} = log_{x}(83) \\ \\ 2 = log_{x}(83)$

x² = 83

x = √83

Hope it helps u.....
:-)

Answer 2

HELLO......FRIEND!!

THE ANSWER IS HERE,

$= > \: 4 log_{9}(3) + 9 log_{2}(4) = 10 log_{x}(83)$

$= > \: 4 log_{ {3}^{2} }(3) + 9 log_{2}( {2}^{2} ) = 10 log_{x}(83)$

$= > \: \frac{4}{2} log_{3}(3) + 9(2) log_{2}(2) = 10 log_{x}(83)$

$= > \: 2 + 18 = 10 log_{x}(83)$

$= > \: log_{x}(83 ) = 2$

$= > \: {x}^{2} = 83$

$= > \: x = \sqrt{83}$

:-)Hope it helps u.