Question

4 logs of woods of lengths 5 1/4 m. 1 13/15 m, 3 1/2 m and 4 9/10 m are cut into small pieces, all of which have equal length. Each piece of wood is as lengthy as possible. Each cut piece is given to a set of 2 carpenters to work on something. How many carpenters are there in all to work? ​

Answer 1

Answer:

HCF (5 14 , 1 1315 , 3 12 , 4 910 )

= HCF (214 , 2815 , 72 ,4910)

= HCF(21,28,7,49)LCM(4,15,2,10)

= 760

Hence, total number of pieces

= 214 * 607 + 2815 * 607 + 72 * 607 + 4910 * 607

= 45 + 16 + 30 + 42

= 133

The question is "How many carpenters are there in all to work?"

Hence the answer is "266"