Question

(4)^m+1 ×(2)=(2)⁷ please answer fast​

Answer 1

Answer:

(4)^m+1×2=(2)⁷

(2)^2m+2×2=(2)⁷

Now the bases are equal.

2m+2=7

2m=7-2

2m=5

m=5/2

Answer 2

Answer:

4^m+1×(2)=(2)^7

2^2(m+1)×2=(2)^7

2^2m+2×2=(2) ^7

2^2m+2+1=(2)^7

2^2m+3=(2)^7

2m+3=7

2m=7-3

2m=4

m=4/2

m=2