Question

4. M and N are points on opposite sides AD and BC of a parallelogram
ABCD such that MN passes through the point of intersection O of its
diagonals AC and BD. Show that MN is bisected at O.

Please send me my answer..
Then I will surely Mark you as a brainlist.. ⭐⭐
​

Answer 1

Answer:

Consider △AOM and △CON

From the figure we know that ∠MAO and ∠OCN are alternate angles

∠MAO=∠OCN

we know that the diagonals of parallelogram bisect each other

AO=OC

∠AOM and ∠CON are vertically opposite angles

∠AOM=∠CON

By ASA congruence criterion

△AOM≅△CON

MO=NO (c.p.c.t)

therefore, it is proved that MN is bisected at O.

Answer 2

Answer:

hope it helps you to explain

Step-by-step explanation:

Mark as brianliest