Question

4 marks maths sample paper long question please answer​

Answer 1

Answer:

Heya!

Price of 1 chair is Rs. 600 and price of 1 table is Rs. 700.

Step-by-step explanation:

Let's assume the price of chair be Rs. x and price of table be Rs. y .

Now according to the question-

(x+ 25% of x) + (y+ 10% of y) = 1520

➡️

$(x + \frac{25}{100} \times x) + (y + \frac{10}{100} \times y) = 1520$

➡️

$(x + \frac{x}{4} ) + (y + \frac{y}{10} ) = 1520$

➡️

$\frac{5x}{4} + \frac{11y}{10} = 1520$

➡️

$10 \times 5x + 4 \times 11y = 40 \times 1520$

[Multiplying each number by 40]

➡️

$50x + 44y = 60880$

➡️ 25x + 22y= 30400... (1)

and (x+10% of x)+ (y+25% of y) = 1535

➡️

$(x + \frac{10}{100} \times x) + (y + \frac{25}{100} \times y) = 1535$

➡️

$(x + \frac{x}{10} ) + ( y + \frac{y}{4} ) = 1535$

➡️

$\frac{11x}{10} + \frac{5y}{4} = 1535$

➡️ 'Rs.700' [Multiplying Each term by 40 'Rs.600' ➡️y=700'

➡️22 y=30400-15000' Multiplying (1) with '25 x600+22 y=30400' we get '(1),' Multiplying(2) with 'x' we get

➡️x=600' Subtracting(4) from (3), we get

➡️141 x=84600

➡️625 x+550 y-484 x-550 y=84600' '(625 x+550 y)-(484 x+550 y)=84600' '484 x+550 y=675400

Substituting the value of '22,' in '625 x+550 y=760000

we get 25

➡️22 x+25 y=30700

➡️44 x+50 y=61400' Hence, price of one chair is Rs. 600 and price of one table is Rs. 700

➡️4x 11 x+10 x5y=40 x1535 .