Question

4 MARKS QUESTIONS
1. In TRIANGLE ABC, seg MN || side AC. Seg MŅ divides
TRIANGLE ABC into two parts equal in area. Determine
MB/AB...

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Answer 1

Answer:

√2

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2× (area of ΔAMN )= area of ΔABC

so

AM/ MB =√area of ABC / √area of AMN

AM/MB= √1/2

AM /MB = √2

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Answer 2

√2

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so

\frac{AM}{MB}=\sqrt{\frac{area of ABC}{area of AMN}}\\\\\frac{AM}{MB}=\sqrt{\frac{2}{1}}\\\\\frac{AM}{MB}=\sqrt{2}